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You are given a 0-indexed array of strings nums, where each string is of equal length and consists of only digits.

You are also given a 0-indexed 2D integer array queries where queries[i] = [ki, trimi]. For each queries[i], you need to:

  • Trim each number in nums to its rightmost trimi digits.
  • Determine the index of the kith smallest trimmed number in nums. If two trimmed numbers are equal, the number with the lower index is considered to be smaller.
  • Reset each number in nums to its original length.

Return an array answer of the same length as queries, where answer[i] is the answer to the ith query.

Note:

  • To trim to the rightmost x digits means to keep removing the leftmost digit, until only x digits remain.
  • Strings in nums may contain leading zeros.

 

Example 1:

Input: nums = ["102","473","251","814"], queries = [[1,1],[2,3],[4,2],[1,2]]
Output: [2,2,1,0]
Explanation:
1. After trimming to the last digit, nums = ["2","3","1","4"]. The smallest number is 1 at index 2.
2. Trimmed to the last 3 digits, nums is unchanged. The 2nd smallest number is 251 at index 2.
3. Trimmed to the last 2 digits, nums = ["02","73","51","14"]. The 4th smallest number is 73.
4. Trimmed to the last 2 digits, the smallest number is 2 at index 0.
   Note that the trimmed number "02" is evaluated as 2.

Example 2:

Input: nums = ["24","37","96","04"], queries = [[2,1],[2,2]]
Output: [3,0]
Explanation:
1. Trimmed to the last digit, nums = ["4","7","6","4"]. The 2nd smallest number is 4 at index 3.
   There are two occurrences of 4, but the one at index 0 is considered smaller than the one at index 3.
2. Trimmed to the last 2 digits, nums is unchanged. The 2nd smallest number is 24.

 

Constraints:

  • 1 <= nums.length <= 100
  • 1 <= nums[i].length <= 100
  • nums[i] consists of only digits.
  • All nums[i].length are equal.
  • 1 <= queries.length <= 100
  • queries[i].length == 2
  • 1 <= ki <= nums.length
  • 1 <= trimi <= nums[i].length

 

Follow up: Could you use the Radix Sort Algorithm to solve this problem? What will be the complexity of that solution?

Companies: DE Shaw

Related Topics:
Array, String, Divide and Conquer, Sorting, Heap (Priority Queue), Radix Sort, Quickselect

Solution 1. Offline Query

// OJ: https://leetcode.com/problems/query-kth-smallest-trimmed-number
// Author: github.com/lzl124631x
// Time: O(Q * NlogN)
// Space: O(Q + N)
class Solution {
public:
    vector<int> smallestTrimmedNumbers(vector<string>& A, vector<vector<int>>& Q) {
        vector<int> ans(Q.size()), id(A.size());
        iota(begin(id), end(id), 0);
        for (int i = 0; i < Q.size(); ++i) Q[i].push_back(i);
        sort(begin(Q), end(Q), [](auto &a, auto &b) { return a[1] > b[1]; });
        int len = A[0].size() + 1;
        for (auto &q : Q) {
            int k = q[0], newLen = q[1], index = q[2];
            if (newLen < len) {
                len = newLen;
                for (auto &s : A) s = s.substr(s.size() - newLen);
                sort(begin(id), end(id), [&](int a, int b) { return A[a] != A[b] ? A[a] < A[b] : a < b; });
            }
            ans[index] = id[k - 1];
        }
        return ans;
    }
};