2278

2278. Percentage of Letter in String (Easy)

Given a string s and a character letter, return the percentage of characters in s that equal letter rounded down to the nearest whole percent.

 

Example 1:

Input: s = "foobar", letter = "o"
Output: 33
Explanation:
The percentage of characters in s that equal the letter 'o' is 2 / 6 * 100% = 33% when rounded down, so we return 33.

Example 2:

Input: s = "jjjj", letter = "k"
Output: 0
Explanation:
The percentage of characters in s that equal the letter 'k' is 0%, so we return 0.

 

Constraints:

• 1 <= s.length <= 100
• s consists of lowercase English letters.
• letter is a lowercase English letter.

Companies: American Express

Related Topics:
String

Similar Questions:

• Sort Characters By Frequency (Medium)

Solution 1.

// OJ: https://leetcode.com/problems/percentage-of-letter-in-string
// Author: github.com/lzl124631x
// Time: O(N)
// Space: O(1)
class Solution {
public:
    int percentageLetter(string s, char letter) {
        int cnt = 0;
        for (char c : s) cnt += c == letter;
        return cnt * 100 / s.size();
    }
};