You are given two strings s
and t
. In one step, you can append any character to either s
or t
.
Return the minimum number of steps to make s
and t
anagrams of each other.
An anagram of a string is a string that contains the same characters with a different (or the same) ordering.
Example 1:
Input: s = "leetcode", t = "coats" Output: 7 Explanation: - In 2 steps, we can append the letters in "as" onto s = "leetcode", forming s = "leetcodeas". - In 5 steps, we can append the letters in "leede" onto t = "coats", forming t = "coatsleede". "leetcodeas" and "coatsleede" are now anagrams of each other. We used a total of 2 + 5 = 7 steps. It can be shown that there is no way to make them anagrams of each other with less than 7 steps.
Example 2:
Input: s = "night", t = "thing" Output: 0 Explanation: The given strings are already anagrams of each other. Thus, we do not need any further steps.
Constraints:
1 <= s.length, t.length <= 2 * 105
s
andt
consist of lowercase English letters.
Similar Questions:
// OJ: https://leetcode.com/problems/minimum-number-of-steps-to-make-two-strings-anagram-ii/
// Author: github.com/lzl124631x
// Time: O(N)
// Space: O(1)
class Solution {
public:
int minSteps(string s, string t) {
int cnt[26] = {}, ans = 0;
for (char c : s) cnt[c - 'a']++;
for (char c : t) cnt[c - 'a']--;
for (int n : cnt) ans += abs(n);
return ans;
}
};
https://leetcode.com/problems/minimum-number-of-steps-to-make-two-strings-anagram-ii/discuss/1802576