You are given two non-negative integers num1
and num2
.
In one operation, if num1 >= num2
, you must subtract num2
from num1
, otherwise subtract num1
from num2
.
- For example, if
num1 = 5
andnum2 = 4
, subtractnum2
fromnum1
, thus obtainingnum1 = 1
andnum2 = 4
. However, ifnum1 = 4
andnum2 = 5
, after one operation,num1 = 4
andnum2 = 1
.
Return the number of operations required to make either num1 = 0
or num2 = 0
.
Example 1:
Input: num1 = 2, num2 = 3 Output: 3 Explanation: - Operation 1: num1 = 2, num2 = 3. Since num1 < num2, we subtract num1 from num2 and get num1 = 2, num2 = 3 - 2 = 1. - Operation 2: num1 = 2, num2 = 1. Since num1 > num2, we subtract num2 from num1. - Operation 3: num1 = 1, num2 = 1. Since num1 == num2, we subtract num2 from num1. Now num1 = 0 and num2 = 1. Since num1 == 0, we do not need to perform any further operations. So the total number of operations required is 3.
Example 2:
Input: num1 = 10, num2 = 10 Output: 1 Explanation: - Operation 1: num1 = 10, num2 = 10. Since num1 == num2, we subtract num2 from num1 and get num1 = 10 - 10 = 0. Now num1 = 0 and num2 = 10. Since num1 == 0, we are done. So the total number of operations required is 1.
Constraints:
0 <= num1, num2 <= 105
Similar Questions:
// OJ: https://leetcode.com/problems/count-operations-to-obtain-zero/
// Author: github.com/lzl124631x
// Time: O(max(num1, num2))
// Space: O(1)
class Solution {
public:
int countOperations(int num1, int num2) {
int ans = 0;
for (; num1 && num2; ++ans) {
if (num1 >= num2) num1 -= num2;
else num2 -= num1;
}
return ans;
}
};
// OJ: https://leetcode.com/problems/count-operations-to-obtain-zero/
// Author: github.com/lzl124631x
// Time: O(max(num1, num2))
// Space: O(1)
class Solution {
public:
int countOperations(int num1, int num2) {
int ans = 0;
while (num1 && num2) {
if (num1 >= num2) ans += num1 / num2, num1 %= num2;
else ans += num2 / num1, num2 %= num1;
}
return ans;
}
};
https://leetcode.com/problems/count-operations-to-obtain-zero/discuss/1766767