You are given a 0-indexed string s
and a 0-indexed integer array spaces
that describes the indices in the original string where spaces will be added. Each space should be inserted before the character at the given index.
- For example, given
s = "EnjoyYourCoffee"
andspaces = [5, 9]
, we place spaces before'Y'
and'C'
, which are at indices5
and9
respectively. Thus, we obtain"Enjoy Your Coffee"
.
Return the modified string after the spaces have been added.
Example 1:
Input: s = "LeetcodeHelpsMeLearn", spaces = [8,13,15] Output: "Leetcode Helps Me Learn" Explanation: The indices 8, 13, and 15 correspond to the underlined characters in "LeetcodeHelpsMeLearn". We then place spaces before those characters.
Example 2:
Input: s = "icodeinpython", spaces = [1,5,7,9] Output: "i code in py thon" Explanation: The indices 1, 5, 7, and 9 correspond to the underlined characters in "icodeinpython". We then place spaces before those characters.
Example 3:
Input: s = "spacing", spaces = [0,1,2,3,4,5,6] Output: " s p a c i n g" Explanation: We are also able to place spaces before the first character of the string.
Constraints:
1 <= s.length <= 3 * 105
s
consists only of lowercase and uppercase English letters.1 <= spaces.length <= 3 * 105
0 <= spaces[i] <= s.length - 1
- All the values of
spaces
are strictly increasing.
// OJ: https://leetcode.com/problems/adding-spaces-to-a-string/
// Author: github.com/lzl124631x
// Time: O(N + M) = O(N)
// Space: O(1) extra space
class Solution {
public:
string addSpaces(string s, vector<int>& A) {
string ans;
ans.reserve(s.size() + A.size()); // Optional: pre-allocate enough space for the answer.
int N = s.size(), j = 0, M = A.size(); // `A[j]` is the next index before which a space should be inserted
for (int i = 0; i < N; ++i) {
if (j < M && i == A[j]) { // If `i == A[j]`, we insert a space
ans += ' ';
++j;
}
ans += s[i];
}
return ans;
}
};
https://leetcode.com/problems/adding-spaces-to-a-string/discuss/1635042/C%2B%2B-Straightforward