Given the head
of a linked list and two integers m
and n
. Traverse the linked list and remove some nodes in the following way:
- Start with the head as the current node.
- Keep the first
m
nodes starting with the current node. - Remove the next
n
nodes - Keep repeating steps 2 and 3 until you reach the end of the list.
Return the head of the modified list after removing the mentioned nodes.
Example 1:
Input: head = [1,2,3,4,5,6,7,8,9,10,11,12,13], m = 2, n = 3 Output: [1,2,6,7,11,12] Explanation: Keep the first (m = 2) nodes starting from the head of the linked List (1 ->2) show in black nodes. Delete the next (n = 3) nodes (3 -> 4 -> 5) show in read nodes. Continue with the same procedure until reaching the tail of the Linked List. Head of the linked list after removing nodes is returned.
Example 2:
Input: head = [1,2,3,4,5,6,7,8,9,10,11], m = 1, n = 3 Output: [1,5,9] Explanation: Head of linked list after removing nodes is returned.
Example 3:
Input: head = [1,2,3,4,5,6,7,8,9,10,11], m = 3, n = 1 Output: [1,2,3,5,6,7,9,10,11]
Example 4:
Input: head = [9,3,7,7,9,10,8,2], m = 1, n = 2 Output: [9,7,8]
Constraints:
- The number of nodes in the list is in the range
[1, 104]
. 1 <= Node.val <= 106
1 <= m, n <= 1000
Follow up: Could you solve this problem by modifying the list in-place?
Companies:
Microsoft
Related Topics:
Linked List
Similar Questions:
- Remove Nth Node From End of List (Medium)
- Remove Zero Sum Consecutive Nodes from Linked List (Medium)
// OJ: https://leetcode.com/problems/delete-n-nodes-after-m-nodes-of-a-linked-list/
// Author: github.com/lzl124631x
// Time: O(N)
// Space: O(1)
class Solution {
public:
ListNode* deleteNodes(ListNode* head, int m, int n) {
auto p = head;
while (p) {
for (int i = 1; i < m && p; ++i) p = p->next;
if (!p) break;
auto tail = p;
p = p->next;
for (int i = 0; i < n && p; ++i) {
auto rm = p;
p = p->next;
delete rm;
}
tail->next = p;
}
return head;
}
};