Given an array nums
of 0s and 1s and an integer k
, return True
if all 1's are at least k
places away from each other, otherwise return False
.
Example 1:
Input: nums = [1,0,0,0,1,0,0,1], k = 2 Output: true Explanation: Each of the 1s are at least 2 places away from each other.
Example 2:
Input: nums = [1,0,0,1,0,1], k = 2 Output: false Explanation: The second 1 and third 1 are only one apart from each other.
Example 3:
Input: nums = [1,1,1,1,1], k = 0 Output: true
Example 4:
Input: nums = [0,1,0,1], k = 1 Output: true
Constraints:
1 <= nums.length <= 10^5
0 <= k <= nums.length
nums[i]
is0
or1
Related Topics:
Array
// OJ: https://leetcode.com/problems/check-if-all-1s-are-at-least-length-k-places-away/
// Author: github.com/lzl124631x
// Time: O(N)
// Space: O(1)
class Solution {
public:
bool kLengthApart(vector<int>& A, int k) {
int prev = -k - 1;
for (int i = 0; i < A.size(); ++i) {
if (A[i] == 0) continue;
if (i - prev <= k) return false;
prev = i;
}
return true;
}
};