We are given a list nums
of integers representing a list compressed with run-length encoding.
Consider each adjacent pair of elements [freq, val] = [nums[2*i], nums[2*i+1]]
(with i >= 0
). For each such pair, there are freq
elements with value val
concatenated in a sublist. Concatenate all the sublists from left to right to generate the decompressed list.
Return the decompressed list.
Example 1:
Input: nums = [1,2,3,4] Output: [2,4,4,4] Explanation: The first pair [1,2] means we have freq = 1 and val = 2 so we generate the array [2]. The second pair [3,4] means we have freq = 3 and val = 4 so we generate [4,4,4]. At the end the concatenation [2] + [4,4,4] is [2,4,4,4].
Example 2:
Input: nums = [1,1,2,3] Output: [1,3,3]
Constraints:
2 <= nums.length <= 100
nums.length % 2 == 0
1 <= nums[i] <= 100
Related Topics:
Array
Similar Questions:
// OJ: https://leetcode.com/problems/decompress-run-length-encoded-list/
// Author: github.com/lzl124631x
// Time: O(N) where N is the length of the output array.
// Space: O(1)
class Solution {
public:
vector<int> decompressRLElist(vector<int>& nums) {
vector<int> ans;
for (int i = 0; i < nums.size(); i += 2) {
for (int j = 0; j < nums[i]; ++j) ans.push_back(nums[i + 1]);
}
return ans;
}
};