Given 2 integers n
and start
. Your task is return any permutation p
of (0,1,2.....,2^n -1)
such that :
p[0] = start
p[i]
andp[i+1]
differ by only one bit in their binary representation.p[0]
andp[2^n -1]
must also differ by only one bit in their binary representation.
Example 1:
Input: n = 2, start = 3 Output: [3,2,0,1] Explanation: The binary representation of the permutation is (11,10,00,01). All the adjacent element differ by one bit. Another valid permutation is [3,1,0,2]
Example 2:
Input: n = 3, start = 2 Output: [2,6,7,5,4,0,1,3] Explanation: The binary representation of the permutation is (010,110,111,101,100,000,001,011).
Constraints:
1 <= n <= 16
0 <= start < 2 ^ n
Related Topics:
Math
// OJ: https://leetcode.com/problems/circular-permutation-in-binary-representation/
// Author: github.com/lzl124631x
// Time: O(2^N)
// Space: O(1)
// Ref: https://leetcode.com/problems/circular-permutation-in-binary-representation/discuss/414203/JavaC%2B%2BPython-4-line-Gray-Code
class Solution {
public:
vector<int> circularPermutation(int n, int start) {
vector<int> ans;
for (int i = 0; i < (1 << n); ++i) ans.push_back(start ^ i ^ (i >> 1));
return ans;
}
};