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Problem0008.py
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Problem0008.py
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Enonce = """
Largest product in a series
Problem 8
The four adjacent digits in the 1000-digit number that have the greatest product are 9 × 9 × 8 × 9 = 5832.
73167176531330624919225119674426574742355349194934
96983520312774506326239578318016984801869478851843
85861560789112949495459501737958331952853208805511
12540698747158523863050715693290963295227443043557
66896648950445244523161731856403098711121722383113
62229893423380308135336276614282806444486645238749
30358907296290491560440772390713810515859307960866
70172427121883998797908792274921901699720888093776
65727333001053367881220235421809751254540594752243
52584907711670556013604839586446706324415722155397
53697817977846174064955149290862569321978468622482
83972241375657056057490261407972968652414535100474
82166370484403199890008895243450658541227588666881
16427171479924442928230863465674813919123162824586
17866458359124566529476545682848912883142607690042
24219022671055626321111109370544217506941658960408
07198403850962455444362981230987879927244284909188
84580156166097919133875499200524063689912560717606
05886116467109405077541002256983155200055935729725
71636269561882670428252483600823257530420752963450
Find the thirteen adjacent digits in the 1000-digit number that have the greatest product. What is the value of this product?
"""
from operator import mul
from functools import reduce
import EulerTools
def main():
print(40*"=")
print(Enonce)
print(40*"-")
digit1000 = [int(i) for i in ''.join("""73167176531330624919225119674426574742355349194934
96983520312774506326239578318016984801869478851843
85861560789112949495459501737958331952853208805511
12540698747158523863050715693290963295227443043557
66896648950445244523161731856403098711121722383113
62229893423380308135336276614282806444486645238749
30358907296290491560440772390713810515859307960866
70172427121883998797908792274921901699720888093776
65727333001053367881220235421809751254540594752243
52584907711670556013604839586446706324415722155397
53697817977846174064955149290862569321978468622482
83972241375657056057490261407972968652414535100474
82166370484403199890008895243450658541227588666881
16427171479924442928230863465674813919123162824586
17866458359124566529476545682848912883142607690042
24219022671055626321111109370544217506941658960408
07198403850962455444362981230987879927244284909188
84580156166097919133875499200524063689912560717606
05886116467109405077541002256983155200055935729725
71636269561882670428252483600823257530420752963450""".replace('\n',''))]
#print(digit1000)
size = 13 #4
greatest_product = 0
index = 0
max_index = len(digit1000)-1 - size
while index < max_index:
factors = digit1000[index : index+size]
#print(f"{index}/{max_index} : {factors}")
while 0 in factors :
index = index + 1
factors = digit1000[index : index+size]
product = reduce(mul, factors, 1)
if product > greatest_product:
greatest_factors = factors
greatest_product = product
index = index + 1
Solution = greatest_product
print(f"The greatest product is {Solution} with factors {greatest_factors}")
greatest_product, greatest_factors = EulerTools.maxLineProduct(digit1000, size)
Solution = greatest_product
print(f"The greatest product is {Solution} with factors {greatest_factors}")
print(40*"-")
print(f"Solution = {Solution}")
print(40*"=")
if __name__ == "__main__":
# execute only if run as a script
main()