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[release-1.31] Optimize CIDR aggregation to improve performance and reduce memory usage #7685

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8 changes: 8 additions & 0 deletions pkg/util/collectionutil/map.go
Original file line number Diff line number Diff line change
Expand Up @@ -16,6 +16,14 @@ limitations under the License.

package fnutil

func Keys[K comparable, V any](m map[K]V) []K {
rv := make([]K, 0, len(m))
for k := range m {
rv = append(rv, k)
}
return rv
}

func Values[K comparable, V any](m map[K]V) []V {
rv := make([]V, 0, len(m))
for _, v := range m {
Expand Down
37 changes: 37 additions & 0 deletions pkg/util/iputil/bits.go
Original file line number Diff line number Diff line change
@@ -0,0 +1,37 @@
/*
Copyright 2024 The Kubernetes Authors.

Licensed under the Apache License, Version 2.0 (the "License");
you may not use this file except in compliance with the License.
You may obtain a copy of the License at

http://www.apache.org/licenses/LICENSE-2.0

Unless required by applicable law or agreed to in writing, software
distributed under the License is distributed on an "AS IS" BASIS,
WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
See the License for the specific language governing permissions and
limitations under the License.
*/

package iputil

// setBitAt sets the bit at the i-th position in the byte slice to the given value.
// Panics if the index is out of bounds.
// For example,
// - setBitAt([0x00, 0x00], 8, 1) returns [0x00, 0b1000_0000].
// - setBitAt([0xff, 0xff], 0, 0) returns [0b0111_1111, 0xff].
func setBitAt(bytes []byte, i int, bit uint8) {
if bit == 1 {
bytes[i/8] |= 1 << (7 - i%8)
} else {
bytes[i/8] &^= 1 << (7 - i%8)
}
}

// bitAt returns the bit at the i-th position in the byte slice.
// The return value is either 0 or 1 as uint8.
// Panics if the index is out of bounds.
func bitAt(bytes []byte, i int) uint8 {
return bytes[i/8] >> (7 - i%8) & 1
}
103 changes: 103 additions & 0 deletions pkg/util/iputil/bits_test.go
Original file line number Diff line number Diff line change
@@ -0,0 +1,103 @@
/*
Copyright 2024 The Kubernetes Authors.

Licensed under the Apache License, Version 2.0 (the "License");
you may not use this file except in compliance with the License.
You may obtain a copy of the License at

http://www.apache.org/licenses/LICENSE-2.0

Unless required by applicable law or agreed to in writing, software
distributed under the License is distributed on an "AS IS" BASIS,
WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
See the License for the specific language governing permissions and
limitations under the License.
*/

package iputil

import (
"testing"

"github.com/stretchr/testify/assert"
)

func Test_bitAt(t *testing.T) {
bytes := []byte{0b1010_1010, 0b0101_0101}
assert.Equal(t, uint8(1), bitAt(bytes, 0))
assert.Equal(t, uint8(0), bitAt(bytes, 1))
assert.Equal(t, uint8(1), bitAt(bytes, 2))
assert.Equal(t, uint8(0), bitAt(bytes, 3))

assert.Equal(t, uint8(1), bitAt(bytes, 4))
assert.Equal(t, uint8(0), bitAt(bytes, 5))
assert.Equal(t, uint8(1), bitAt(bytes, 6))
assert.Equal(t, uint8(0), bitAt(bytes, 7))

assert.Equal(t, uint8(0), bitAt(bytes, 8))
assert.Equal(t, uint8(1), bitAt(bytes, 9))
assert.Equal(t, uint8(0), bitAt(bytes, 10))
assert.Equal(t, uint8(1), bitAt(bytes, 11))

assert.Equal(t, uint8(0), bitAt(bytes, 12))
assert.Equal(t, uint8(1), bitAt(bytes, 13))
assert.Equal(t, uint8(0), bitAt(bytes, 14))
assert.Equal(t, uint8(1), bitAt(bytes, 15))

assert.Panics(t, func() { bitAt(bytes, 16) })
}

func Test_setBitAt(t *testing.T) {
tests := []struct {
name string
initial []byte
index int
bit uint8
expected []byte
}{
{
name: "Set first bit to 1",
initial: []byte{0b0000_0000},
index: 0,
bit: 1,
expected: []byte{0b1000_0000},
},
{
name: "Set last bit to 1",
initial: []byte{0b0000_0000},
index: 7,
bit: 1,
expected: []byte{0b0000_0001},
},
{
name: "Set middle bit to 1",
initial: []byte{0b0000_0000},
index: 4,
bit: 1,
expected: []byte{0b0000_1000},
},
{
name: "Set bit to 0",
initial: []byte{0b1111_1111},
index: 3,
bit: 0,
expected: []byte{0b1110_1111},
},
{
name: "Set bit in second byte",
initial: []byte{0b0000_0000, 0b0000_0000},
index: 9,
bit: 1,
expected: []byte{0b0000_0000, 0b0100_0000},
},
}

for _, tt := range tests {
t.Run(tt.name, func(t *testing.T) {
setBitAt(tt.initial, tt.index, tt.bit)
assert.Equal(t, tt.expected, tt.initial)
})
}

assert.Panics(t, func() { setBitAt([]byte{0x00}, 8, 1) })
}
105 changes: 103 additions & 2 deletions pkg/util/iputil/prefix.go
Original file line number Diff line number Diff line change
Expand Up @@ -17,8 +17,10 @@ limitations under the License.
package iputil

import (
"bytes"
"fmt"
"net/netip"
"sort"
)

// IsPrefixesAllowAll returns true if one of the prefixes allows all addresses.
Expand Down Expand Up @@ -61,9 +63,108 @@ func GroupPrefixesByFamily(vs []netip.Prefix) ([]netip.Prefix, []netip.Prefix) {
return v4, v6
}

// AggregatePrefixes aggregates prefixes.
// Overlapping prefixes are merged.
// ContainsPrefix checks if prefix p fully contains prefix o.
// It returns true if o is a subset of p, meaning all addresses in o are also in p.
// This is true when p overlaps with o and p has fewer or equal number of bits than o.
func ContainsPrefix(p netip.Prefix, o netip.Prefix) bool {
return p.Bits() <= o.Bits() && p.Overlaps(o)
}

// mergeAdjacentPrefixes attempts to merge two adjacent prefixes into a single prefix.
// It returns the merged prefix and a boolean indicating success.
// Note: This function only merges adjacent prefixes, not overlapping ones.
func mergeAdjacentPrefixes(p1, p2 netip.Prefix) (netip.Prefix, bool) {
// Merge neighboring prefixes if possible
if p1.Bits() != p2.Bits() || p1.Bits() == 0 {
return netip.Prefix{}, false
}

var (
bits = p1.Bits()
p1Bytes = p1.Addr().AsSlice()
p2Bytes = p2.Addr().AsSlice()
)
if bitAt(p1Bytes, bits-1) == 0 {
setBitAt(p1Bytes, bits-1, 1)
} else {
setBitAt(p2Bytes, bits-1, 1)
}
if !bytes.Equal(p1Bytes, p2Bytes) {
return netip.Prefix{}, false
}

rv, _ := p1.Addr().Prefix(bits - 1)
return rv, true
}

// aggregatePrefixesForSingleIPFamily merges overlapping or adjacent prefixes into a single prefix.
// The input prefixes must be the same IP family (IPv4 or IPv6).
// For example,
// - [192.168.0.0/32, 192.168.0.1/32] -> [192.168.0.0/31] (adjacent)
// - [192.168.0.0/24, 192.168.0.1/32] -> [192.168.1.0/24] (overlapping)
func aggregatePrefixesForSingleIPFamily(prefixes []netip.Prefix) []netip.Prefix {
if len(prefixes) <= 1 {
return prefixes
}

sort.Slice(prefixes, func(i, j int) bool {
addrCmp := prefixes[i].Addr().Compare(prefixes[j].Addr())
if addrCmp == 0 {
return prefixes[i].Bits() < prefixes[j].Bits()
}
return addrCmp < 0
})

var rv = []netip.Prefix{prefixes[0]}

for i := 1; i < len(prefixes); i++ {
last, p := rv[len(rv)-1], prefixes[i]
if ContainsPrefix(last, p) {
// Skip overlapping prefixes
continue
}
rv = append(rv, p)

// Merge adjacent prefixes if possible
for len(rv) >= 2 {
// Merge the last two prefixes if they are adjacent
p, ok := mergeAdjacentPrefixes(rv[len(rv)-2], rv[len(rv)-1])
if !ok {
break
}

// Replace the last two prefixes with the merged prefix
rv = rv[:len(rv)-2]
rv = append(rv, p)
}
}
return rv
}

// AggregatePrefixes merges overlapping or adjacent prefixes into a single prefix.
// It combines prefixes that can be represented by a larger, more inclusive prefix.
//
// Examples:
// - Adjacent: [192.168.0.0/32, 192.168.0.1/32] -> [192.168.0.0/31]
// - Overlapping: [192.168.0.0/24, 192.168.0.1/32] -> [192.168.0.0/24]
func AggregatePrefixes(prefixes []netip.Prefix) []netip.Prefix {
var (
v4, v6 = GroupPrefixesByFamily(prefixes)
)

return append(aggregatePrefixesForSingleIPFamily(v4), aggregatePrefixesForSingleIPFamily(v6)...)
}

// AggregatePrefixesWithPrefixTree merges overlapping or adjacent prefixes into a single prefix.
//
// This function uses a prefix tree to aggregate the input prefixes. While it achieves
// the same result as AggregatePrefixes, it is less efficient. For better performance,
// use AggregatePrefixes instead.
//
// Examples:
// - Adjacent: [192.168.0.0/32, 192.168.0.1/32] -> [192.168.0.0/31]
// - Overlapping: [192.168.0.0/24, 192.168.0.1/32] -> [192.168.0.0/24]
func AggregatePrefixesWithPrefixTree(prefixes []netip.Prefix) []netip.Prefix {
var (
v4, v6 = GroupPrefixesByFamily(prefixes)
v4Tree = newPrefixTreeForIPv4()
Expand Down
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