Formula 6.5, missing factor 2

[Maesla]

Following the issue 11 , I have a question regarding formula 6.5
In the book, Formula 6.5 stands for

$\ddot{p}=(p_t-p_0)\frac{1}{t^2}-\dot{p_0}$

As issue issue 11 says, there is a t missing in the formula, so it should be

$\ddot{p}=(p_t-p_0)\frac{1}{t^2}-\frac{\dot{p_0}}{t}$

But, if this formula comes, as I suspect, from uniform acceleration motion, since where are guessing that during all the frame we are applying the same acceleration to get the particle exactly to the position we want,
$p_t=p_0 +\dot{p_0}t+\frac{1}{2}\ddot{p}t^2$

Are we missing the 2 factor as well in the final formula, getting the following formula as the corrected 6.5?
$\ddot{p}=\frac{2}{t^2}(p_t-p_0)-\frac{2}{t}\dot{p_0}$

cyclone-physics/src/pfgen.cpp

Line 177 in d75c8d9

Vector3 accel = (target - position) * ((real)1.0 / (duration*duration)) -