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记一个将数组作为函数参数传递的小技巧 #3

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ibufu opened this issue Aug 31, 2016 · 0 comments

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ibufu commented Aug 31, 2016

const bar = [1, 2, 3];
foo(...bar);

等同于：

foo.apply(this, bar);

一个用例：

const middleware = [
    thunk,
    api,
    !__NODE__ && createLogger(),
].filter(Boolean);

export default function configureStore(initialState) {
    const store = createStore(
        rootReducer,
        initialState,
        compose(
            applyMiddleware(...middleware),
        )
    );

    return store;
}

redux 的 applyMiddleware 方法不能接受数组，可以利用这个方法方便地根据环境改变参数。

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