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论文说当 block of meaningful bits 不在先前的范围内,用 5 bits 存前导零的数量,6 bits 存 meaningful bits 的数量,最后存 meaningful bits, value 的类型限定为双精度浮点数,总共有 64 位,2 ^ 6 = 64,不应该用 6 bits 来存前导零的数量,为什么用 5 bits?而 meaningful bits 的数量也是用 6 bits。我看论文时理解不了这点,我在 GitHub 上看到了你的实现,就想向你请教一下。
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论文说当 block of meaningful bits 不在先前的范围内,用 5 bits 存前导零的数量,6 bits 存 meaningful bits 的数量,最后存 meaningful bits, value 的类型限定为双精度浮点数,总共有 64 位,2 ^ 6 = 64,不应该用 6 bits 来存前导零的数量,为什么用 5 bits?而 meaningful bits 的数量也是用 6 bits。我看论文时理解不了这点,我在 GitHub 上看到了你的实现,就想向你请教一下。
The text was updated successfully, but these errors were encountered: