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do you have xgboost classifier but not regression? #68
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@Sandy4321 It should suffice to replace class SquaredError():
def __init__(self):
pass
def loss(self, y, y_pred):
return 0.5 * ((y - y_pred) ** 2)
# gradient w.r.t y_pred
def gradient(self, y, y_pred):
return -(y - y_pred)
# w.r.t y_pred
def hess(self, y, y_pred):
return 1 |
Great thanks ft(x)=wq(x),w∈RT,q:Rd→{1,2,⋯,T}. Ω(f)=γT+12λ∑j=1Tw2j |
@Sandy4321 I don't think this example has all the regularization mechanism as XGBoost does, as the example is quite simplified. There are |
@hcho3 hi, sorry to interrupt. I am trying to learn xgboost by this project. I come up with some problem with function "def _gain(self, y, y_pred):" in supervised_learning/decision_tree.py. def _gain(self, y, y_pred): the variable nominator says ((y*self.loss.gradient(y, y_pred).sum())^2, but according to xgboost doc https://xgboost.readthedocs.io/en/latest/tutorials/model.html, shouldn't it be (self.loss.gradient(y, y_pred).sum())^2? I know I am wrong by changing this line to what I thought, because after changing this line the example just got wrong result. But I still don't know why it's like this. Could you explain it to me? thanks |
do you have xgboost classifier in
https://github.com/eriklindernoren/ML-From-Scratch/blob/master/mlfromscratch/supervised_learning/xgboost.py
but not regression?
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