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111.minimum-depth-of-binary-tree.cpp
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111.minimum-depth-of-binary-tree.cpp
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/*
* @lc app=leetcode id=111 lang=cpp
*
* [111] Minimum Depth of Binary Tree
*
* https://leetcode.com/problems/minimum-depth-of-binary-tree/description/
*
* algorithms
* Easy (42.76%)
* Likes: 4962
* Dislikes: 1020
* Total Accepted: 848.9K
* Total Submissions: 2M
* Testcase Example: '[3,9,20,null,null,15,7]'
*
* Given a binary tree, find its minimum depth.
*
* The minimum depth is the number of nodes along the shortest path from the
* root node down to the nearest leaf node.
*
* Note: A leaf is a node with no children.
*
*
* Example 1:
*
*
* Input: root = [3,9,20,null,null,15,7]
* Output: 2
*
*
* Example 2:
*
*
* Input: root = [2,null,3,null,4,null,5,null,6]
* Output: 5
*
*
*
* Constraints:
*
*
* The number of nodes in the tree is in the range [0, 10^5].
* -1000 <= Node.val <= 1000
*
*
*/
// @lc code=start
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
int minDepth(TreeNode* root) {
if(!root) return 0;
int L = minDepth(root->left),R = minDepth(root->right);
return 1 + (min(L,R)?min(L,R):max(L,R));
}
};
// @lc code=end