- Get the inorder of BST which is sorted.
- We can find min diff by
next-prev
in inorder vector.
class Solution {
private:
void inorder(TreeNode* root, vector<int>& v)
{
if (root == nullptr) return;
inorder(root->left, v);
v.push_back(root->val);
inorder(root->right, v);
}
public:
int getMinimumDifference(TreeNode* root)
{
int mindiff = INT_MAX;
vector<int> v;
inorder(root, v);
int n = v.size();
for (int i = 0; i < n - 1; i++)
mindiff = min(mindiff, v[i + 1] - v[i]);
return mindiff;
}
};
Without Extra O(N) space in order
- We can maintain prev value to calculate min diff while traversing inorder in BST.
class Solution {
private:
int minDiff = INT_MAX;
int prev = -1;
void inorder(TreeNode* root){
if(root == NULL) return;
inorder(root->left);
if(prev != -1) minDiff = min(minDiff, root->val - prev);
prev = root->val;
inorder(root->right);
}
public:
int
getMinimumDifference(TreeNode* root)
{
inorder(root);
return minDiff;
}
};