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Json参数请求 #30
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由于paramsForApi:方法返回的是Dictionary格式,并在内部实现逐层传递的都是dictionary。 1.用servicetype的方式解决不了 |
其实你可以在service里用request generator来生产你需要的request请求的,这需要自己实现一个service。 |
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框架只有Form表单的请求方式,入参必须是字典,请问如何优雅的扩展JSON MULTIPART的请求方式
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