diff --git a/Chapter-10-Sorting-and-Searching/10.2-Group-Anagrams/10.2-Group-Anagrams.cpp b/Chapter-10-Sorting-and-Searching/10.2-Group-Anagrams/10.2-Group-Anagrams.cpp
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+// Question 10.2
+// Group Anagrams
+//
+//  Explanation:
+//  To check if two strings are anagrams of each other, we use a simple function that sorts them (by character) and
+//  checks if they are the same string. To sort the string array we start from the leftmost element and compare it to
+//  all other elements, moving all the anagrams to the right of it. Then we go to the first element that isn't an
+//  anagram of these and do the same process until we reach the end of the array.
+
+#include<bits/stdc++.h>
+using namespace std;
+
+vector<vector<string> > groupAnagrams(vector<string>& strs) 
+{
+    vector<vector<string>> result ;
+        
+        unordered_map<string, vector<string>> mp ;
+        
+        for(string c : strs )
+        {
+            string s=  c ;
+            sort(s.begin() , s.end()) ;
+                       
+            mp[s].push_back(c) ;
+        }
+        
+        for(auto c : mp)
+        {
+            result.push_back(c.second) ;
+        }
+        
+        return result ;
+}
+
+int main()
+{   
+    int test_cases;
+    cin>>test_cases ;
+    while(test_cases)
+    {
+        int n; 
+        cin>>n ;
+        vector<string> str_list(n) ;
+        for(int i=0 ; i<n ; i++)
+        {
+            cin>>str_list[i] ;
+        }
+
+        vector<vector<string>> Ans = groupAnagrams(str_list) ;
+        
+        //sorting the Ans-Vector which contains our Grouped Anagrams
+        sort(Ans.begin() , Ans.end()); 
+
+        //Printing the Groups
+        for(int i=0 ; i<Ans.size(); i++)
+        {
+            for(int j=0 ; j<Ans[i].size() ; j++)
+            {
+                cout<<Ans[i][j]<<" " ;
+            }
+            cout<<endl;
+        }
+    }
+    
+    return 0;
+}