diff --git a/daily/cpp/Nov-28-Number-of-ways-to-divide-a-long-corridor.cpp b/daily/cpp/Nov-28-Number-of-ways-to-divide-a-long-corridor.cpp
index 290ca29..92f16b5 100644
--- a/daily/cpp/Nov-28-Number-of-ways-to-divide-a-long-corridor.cpp
+++ b/daily/cpp/Nov-28-Number-of-ways-to-divide-a-long-corridor.cpp
@@ -11,7 +11,8 @@ class Solution {
       if (corridor[i] == 'S') {
         chairs++;
 
-        while (++i < corridor.size() && corridor[i] != 'S');
+        while (++i < corridor.size() && corridor[i] != 'S')
+          ;
         // the while increment i and check each character in the corridor
         // string. the loop continues until the end of the string or until the
         // next chair.