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parserM4.py
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parserM4.py
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from selenium import webdriver
import time
import datetime
import pandas as pd
import re
from bs4 import BeautifulSoup
from selenium.common.exceptions import TimeoutException
from datetime import datetime, timedelta
import requests
import json
import platform
from selenium.webdriver.chrome.options import Options
import signal
columns = ['Height', 'Transactions', 'AvgFee/Tx', 'RewardFee', 'Time']
def openPhantom():
#if platform.system() == 'Darwin':
d = webdriver.PhantomJS()
d.set_window_size(1124, 850)
#chrome_options = webdriver.ChromeOptions()
#chrome_options.add_argument('headless')
# chrome_options.add_argument('--no-sandbox')
#d = webdriver.Chrome('/usr/local/bin/chromedriver', chrome_options=chrome_options)
#else:
# d = webdriver.PhantomJS('/home/alexattia/node_modules/.bin/ghostdriver')
# d = webdriver.PhantomJS(executable_path=r'C:\Users\youce\Anaconda3\Library\bin\phantomjs.exe')
d.set_page_load_timeout(10)
#d.service.process.send_signal(signal.SIGTERM)
return d
def parse_bitinfocharts():
# chrome_options = Options()
# chrome_options.add_argument("--headless")
# d = webdriver.Chrome(chrome_options=chrome_options)
d = openPhantom()
try:
d.get("https://bitinfocharts.com/")
except:
pass
# click to get Doge info
time.sleep(2)
d.save_screenshot('screen.png')
d.find_element_by_xpath("//span[@id='s_doge'][@class='label s_coins']").click()
table = d.find_element_by_id('main_body').find_element_by_tag_name('tbody').get_attribute('innerHTML')
bs = BeautifulSoup(table, "lxml")
d.quit()
df = pd.DataFrame()
df['Columns'] = [k.find('td').getText() for k in bs.find_all('tr')]
for crypto in ['btc', 'eth', 'ltc', 'dash', 'doge']:
df[crypto.upper()] = [p.getText() for p in bs.find_all(class_='c_%s' % crypto)]
df2 = df.copy()
stopwords = ['BTC', 'ETH', 'LTC', 'DASH', 'DOGE']
def remove_chars(x):
num = re.sub('[^0-9]', '', x)
if len(str(num)) < 3:
return x
else:
return num
def convert_number(x):
return float(x.replace(',', ''))
def remove_crypt(x):
for k in stopwords:
if k in x:
return convert_number(x[:x.index(k)])
def clean_reward(x):
for k in stopwords:
if k in x:
x = x[:x.index(k)]
return tuple(map(float, x.replace(',', '').split('+')))
df2.loc[0] = df2.loc[0].apply(lambda x: x[:x.index('(')] if '(' in x else x)
df2.loc[1] = df2.loc[1].apply(remove_chars)
df2.loc[2] = df2.loc[2].apply(lambda x: convert_number(x[x.find('$') + 1:x.find('USD')]) if 'USD' in x else x)
df2.loc[3] = df2.loc[3].apply(lambda x: convert_number(x[x.find('$') + 1:x.find('USD')]) if 'USD' in x else x)
df2.iloc[4, 1:] = df2.iloc[4, 1:].apply(convert_number)
for p in range(6, 10):
df2.iloc[p, 1:] = df2.iloc[p, 1:].apply(remove_crypt)
df2.iloc[14, 1:] = df2.iloc[14, 1:].apply(clean_reward)
df2.iloc[15, 1:] = df2.iloc[15, 1:].apply(clean_reward)
return df2
def parse_one_day_btc(year, month, day, verbose=False):
"""
Scrapper to get all the block of one day on BTC.com
:param date: info about the day to scrap
"""
d = openPhantom()
try:
d.get("https://btc.com/block?date=%s-%02d-%02d" % (year, month, day))
table = d.find_element_by_class_name('table').find_element_by_tag_name('tbody').get_attribute('innerHTML')
except TimeoutException as ex:
time.sleep(1)
table = d.find_element_by_class_name('table').find_element_by_tag_name('tbody').get_attribute('innerHTML')
bs = BeautifulSoup(table, "lxml")
d.quit()
row = bs.find_all('tr')[1:]
cols = pd.Series([k.getText() for k in bs.find_all('tr')[0].find_all('th')][:-1]),
values = pd.DataFrame([[k.getText().strip() for k in r.find_all('td')][:-1] for r in row])
if verbose:
print('Day %s/%s done!' % (day, month))
return cols, values
def parse_btc(n_days=10, first_time=None):
"""
Parsing multiple days all the block from BTC.com
:param n_days: number of days to parse
:return: "clean" dataframe
"""
now = datetime.now()
if first_time:
n_days = (now - first_time).days
df = pd.DataFrame()
if n_days == 0:
n_days = 1
for i in range(n_days):
date = now - timedelta(i)
cols, temp = parse_one_day_btc(date.year, date.month, date.day)
df = pd.concat([df, temp])
df = df.reset_index(drop=True)
df.columns = cols[0]
if len(df.columns) > 8:
del df[df.columns[1]]
# Remove ',' in number
for col in df.columns[:6]:
df[col] = df[col].apply(lambda x: float(x.replace(',', '')))
df['RewardFee'] = df[df.columns[6]].apply(lambda x: float(x[x.index('+ ') + 2:x.index(' BTC')]))
print(df[columns[4]][:7])
df[columns[4]] = pd.to_datetime(df[columns[4]], format='%Y-%m-%d %H:%M:%S')
return df.rename(columns={'Tx Count': columns[1], 'Avg Fee Per Tx': columns[2]})
def parse_one_day_ether(p_number, verbose=False):
"""
Scrapper to get all the block of one day on EtherScan
:param p_number: page number to scrap
:param verbose: boolean for verbose
"""
d = openPhantom()
try:
d.get("https://etherscan.io/blocks?p=%s" % p_number)
except TimeoutException:
pass
table = d.find_element_by_class_name('table').find_element_by_tag_name('tbody').get_attribute('innerHTML')
thead = d.find_element_by_class_name('table').find_element_by_tag_name('thead').get_attribute('innerHTML')
bs = BeautifulSoup(table, "lxml")
thead = BeautifulSoup(thead, "lxml")
d.quit()
cols = pd.Series([k.getText() for k in thead.find_all('th')])
row = bs.find_all('tr')
values = pd.DataFrame([[k.getText().strip() for k in r.find_all('td')] for r in row])
time = pd.Series([r.find_all('td')[1].span.attrs['data-original-title'] for r in row])
if verbose:
print('Page %s done' % p_number)
return cols, values, time
def parse_ether(n_blocks):
"""
Parsing multiple days all the block from EtherScan.
Caution it could be long : 0.16s/block
:param n_blocks: number of blocks to parse
:return: "clean" dataframe
"""
df = pd.DataFrame()
page_number_max = int(n_blocks / 25) # 25 block per page
for dd in range(1, page_number_max + 1):
cols, temp, time = parse_one_day_ether(dd)
temp.columns = cols.values
temp['Age'] = time
df = pd.concat([df, temp])
# Remove duplicates, Ethereum blocks can be faster than scrapping
df = df.drop_duplicates(df.columns[0])
df = df.reset_index(drop=True)
# Cleaning
df[df.columns[8]] = df[df.columns[8]].apply(lambda x: float(x[:x.find(' E')]))
df[df.columns[7]] = df[df.columns[7]].apply(
lambda x: float(x[:x.find(' G')].replace(',', '')) if not '-' in x else 0)
df[df.columns[2]] = df[df.columns[2]].apply(float)
df = df.rename(columns={'txn': columns[1],
'Age': columns[4]})
df[columns[3]] = df['Reward'] - 3
df[columns[2]] = df[columns[3]] / df[columns[1]]
df[columns[4]] = pd.to_datetime(df[columns[4]], format="%b-%d-%Y %I:%M:%S %p")
return df
def parse_one_block_blockcypher(blockchain, block_number):
"""
Parsing one LTC block usting BlockCypher API
Hourly rate : 200 blocks
:param blockchain: Cryptocurrency symbol (e.g ltc, doge)
:param block_number: block number to parse
:return: dict with values, -1 if not good status_code
"""
results = {}
response = requests.get('https://api.blockcypher.com/v1/%s/main/blocks/%s' % (blockchain, block_number))
if response.status_code == 200:
r = json.loads(response.content.decode('latin1'))
results[columns[3]] = r['fees'] * 1E-8 # convert to non-satoshi
results[columns[0]] = r['height']
results[columns[1]] = r['n_tx']
results['time'] = r['time']
results['nonce'] = r['nonce']
results['blockchain'] = r["chain"]
return results
else:
return -1
def get_first_block(blockchain):
"""
Use BitInfoCharts to get the first ltc block number
:return: block number as int
"""
response = requests.get('https://api.blockcypher.com/v1/%s/main' % blockchain)
if response.status_code == 200:
return int(json.loads(response.content.decode('latin1'))['height'])
elif response.status_code == 429:
print('Too many requests')
return -1
def parse_blockcypher(blockchain, first_block=None, n_block=200):
"""
Parsing multiple crypto blocks usting BlockCypher API
:param blockchain: Cryptocurrency symbol (e.g ltc, doge)
:param first_block: most recent block to parse
:param last_block: last block to parse (< first_block)
:return: list of dictionaries for each block
"""
r = []
if not first_block:
first_block = get_first_block(blockchain)
for block_number in range(first_block, first_block - n_block, -1):
block = parse_one_block_blockcypher(blockchain, block_number)
if block != -1:
r.append(block)
else:
print('Error after block number %s (%s blocks done)' % (block_number, first_block - block_number))
break
df = pd.DataFrame(r)
df[columns[4]] = pd.to_datetime(df['time'], format="%Y-%m-%dT%H:%M:%SZ")
df[columns[2]] = df[columns[3]] / df[columns[1]]
return df