"""
Problem Name : Binary Tree Cameras
Problem URL : https://leetcode.com/problems/binary-tree-cameras/
Description :
Return the minimum number of cameras needed to monitor all nodes of the tree.
Difficulty : Hard
Language : Python3
Category : Algorithms
"""
class Solution:
def minCameraCover(self, root: Optional[TreeNode]) -> int:
def calcState(node):
if not node:
return [0, 0, float('inf')]
left = calcState(node.left)
right = calcState(node.right)
a = left[1] + right[1]
b = min(left[2] + min(right[1:]), right[2] + min(left[1:]))
c = 1 + min(left) + min(right)
return [a, b, c]
return min(calcState(root)[1:])
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right