/**
Problem Name : Minimum Cost to Move Chips to The Same Position
Problem URL : https://leetcode.com/problems/path-sum/
Description :
We have n chips, where the position of the ith chip is position[i].
We need to move all the chips to the same position.
In one step, we can change the position of the ith chip from position[i] to:
position[i] + 2 or position[i] - 2 with cost = 0.
position[i] + 1 or position[i] - 1 with cost = 1.
Return the minimum cost needed to move all the chips to the same position.
Difficulty : Easy
Language : C#
Category : Algorithms - Greedy
*/
public class Solution
{
public int MinCostToMoveChips(int[] position)
{
int even = 0;
int odd = 0;
for(int i = 0; i < position.Length; i++)
if(position[i] % 2 == 0)
even++;
else
odd++;
return even < odd ? even : odd;
}
}