Given a string S
of '('
and ')'
parentheses, we add the minimum number of parentheses ( '('
or ')'
, and in any positions ) so that the resulting parentheses string is valid.
Formally, a parentheses string is valid if and only if:
- It is the empty string, or
- It can be written as
AB
(A
concatenated withB
), whereA
andB
are valid strings, or - It can be written as
(A)
, whereA
is a valid string.
Given a parentheses string, return the minimum number of parentheses we must add to make the resulting string valid.
Example 1:
Input: "())" Output: 1
Example 2:
Input: "(((" Output: 3
Example 3:
Input: "()" Output: 0
Example 4:
Input: "()))((" Output: 4
Note:
S.length <= 1000
S
only consists of'('
and')'
characters.
Companies:
Facebook, ServiceNow
// OJ: https://leetcode.com/problems/minimum-add-to-make-parentheses-valid/
// Author: github.com/lzl124631x
// Time: O(N)
// Space: O(1)
class Solution {
public:
int minAddToMakeValid(string S) {
int left = 0, invalidRight = 0;
for (char c : S) {
if (c == '(') left++;
else if (!left) invalidRight++;
else --left;
}
return left + invalidRight;
}
};