We are given two strings, A
and B
.
A shift on A
consists of taking string A
and moving the leftmost character to the rightmost position. For example, if A = 'abcde'
, then it will be 'bcdea'
after one shift on A
. Return True
if and only if A
can become B
after some number of shifts on A
.
Example 1: Input: A = 'abcde', B = 'cdeab' Output: true Example 2: Input: A = 'abcde', B = 'abced' Output: false
Note:
A
andB
will have length at most100
.
// OJ: https://leetcode.com/problems/rotate-string/
// Author: github.com/lzl124631x
// Time: O(N^2)
// Space: O(N)
class Solution {
public:
bool rotateString(string A, string B) {
return A.size() == B.size() && (A + A).find(B) != string::npos;
}
};