Given an unsorted array of integers, find the length of longest continuous
increasing subsequence (subarray).
Example 1:
Input: [1,3,5,4,7] Output: 3 Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. Even though [1,3,5,7] is also an increasing subsequence, it's not a continuous one where 5 and 7 are separated by 4.
Example 2:
Input: [2,2,2,2,2] Output: 1 Explanation: The longest continuous increasing subsequence is [2], its length is 1.
Note: Length of the array will not exceed 10,000.
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Related Topics:
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Similar Questions:
// OJ: https://leetcode.com/problems/longest-continuous-increasing-subsequence/
// Author: github.com/lzl124631x
// Time: O(N)
// Space: O(1)
class Solution {
public:
int findLengthOfLCIS(vector<int>& nums) {
int ans = 0, len = 0, prev = INT_MAX;
for (int n : nums) {
if (n > prev) ++len;
else len = 1;
prev = n;
ans = max(ans, len);
}
return ans;
}
};