Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.
Given linked list -- head = [4,5,1,9], which looks like following:
Example 1:
Input: head = [4,5,1,9], node = 5 Output: [4,1,9] Explanation: You are given the second node with value 5, the linked list should become 4 -> 1 -> 9 after calling your function.
Example 2:
Input: head = [4,5,1,9], node = 1 Output: [4,5,9] Explanation: You are given the third node with value 1, the linked list should become 4 -> 5 -> 9 after calling your function.
Note:
- The linked list will have at least two elements.
- All of the nodes' values will be unique.
- The given node will not be the tail and it will always be a valid node of the linked list.
- Do not return anything from your function.
Related Topics:
Linked List
Similar Questions:
// OJ: https://leetcode.com/problems/delete-node-in-a-linked-list/
// Author: github.com/lzl124631x
// Time: O(1)
// Space: O(1)
class Solution {
public:
void deleteNode(ListNode* node) {
node->val = node->next->val;
auto del = node->next;
node->next = del->next;
delete(del);
}
};