Merge two sorted linked lists and return it as a sorted list. The list should be made by splicing together the nodes of the first two lists.
Example 1:
Input: l1 = [1,2,4], l2 = [1,3,4] Output: [1,1,2,3,4,4]
Example 2:
Input: l1 = [], l2 = [] Output: []
Example 3:
Input: l1 = [], l2 = [0] Output: [0]
Constraints:
- The number of nodes in both lists is in the range
[0, 50]
. -100 <= Node.val <= 100
- Both
l1
andl2
are sorted in non-decreasing order.
Related Topics:
Linked List, Recursion
Companies:
Amazon, Microsoft, Facebook, Google, Adobe, Apple, Bloomberg, Yahoo, Arista Networks, Uber, Indeed, Cisco, Tencent, Airbnb, Oracle, IBM, Huawei, Paypal, Yandex
Similar Questions:
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- Merge Sorted Array (Easy)
- Sort List (Medium)
- Shortest Word Distance II (Medium)
- Add Two Polynomials Represented as Linked Lists (Medium)
// OJ: https://leetcode.com/problems/merge-two-sorted-lists/
// Author: github.com/lzl124631x
// Time: O(A + B)
// Space: O(1)
class Solution {
public:
ListNode* mergeTwoLists(ListNode* a, ListNode* b) {
ListNode head, *tail = &head;
while (a && b) {
if (a->val <= b->val) {
tail->next = a;
a = a->next;
} else {
tail->next = b;
b = b->next;
}
tail = tail->next;
}
tail->next = a ? a : b;
return head.next;
}
};