Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋
times.
You may assume that the array is non-empty and the majority element always exist in the array.
Example 1:
Input: [3,2,3] Output: 3
Example 2:
Input: [2,2,1,1,1,2,2] Output: 2
Companies:
Amazon, Google, Microsoft, Facebook
Related Topics:
Array, Divide and Conquer, Bit Manipulation
// OJ: https://leetcode.com/problems/majority-element/
// Author: github.com/lzl124631x
// Time: O(N)
// Space: O(1)
class Solution {
public:
int majorityElement(vector<int>& nums) {
int ans = 0, cnt = 0;
for (int n : nums) {
if (ans == n) ++cnt;
else if (cnt > 0) --cnt;
else {
ans = n;
cnt = 1;
}
}
return ans;
}
};