Given head
which is a reference node to a singly-linked list. The value of each node in the linked list is either 0 or 1. The linked list holds the binary representation of a number.
Return the decimal value of the number in the linked list.
Example 1:
Input: head = [1,0,1] Output: 5 Explanation: (101) in base 2 = (5) in base 10
Example 2:
Input: head = [0] Output: 0
Example 3:
Input: head = [1] Output: 1
Example 4:
Input: head = [1,0,0,1,0,0,1,1,1,0,0,0,0,0,0] Output: 18880
Example 5:
Input: head = [0,0] Output: 0
Constraints:
- The Linked List is not empty.
- Number of nodes will not exceed
30
. - Each node's value is either
0
or1
.
Related Topics:
Linked List, Bit Manipulation
// OJ: https://leetcode.com/problems/convert-binary-number-in-a-linked-list-to-integer/
// Author: github.com/lzl124631x
// Time: O(N)
// Space: O(1)
class Solution {
public:
int getDecimalValue(ListNode* head) {
int ans = 0;
while (head) {
ans = (ans << 1) + head->val;
head = head->next;
}
return ans;
}
};