day-162.cpp

/*
  Compare Version Numbers


Compare two version numbers version1 and version2.
If version1 > version2 return 1; if version1 < version2 return -1;otherwise
return 0.

You may assume that the version strings are non-empty and contain only digits
and the . character.

The . character does not represent a decimal point and is used to separate
number sequences.

For instance, 2.5 is not "two and a half" or "half way to version three", it is
the fifth second-level revision of the second first-level revision.

You may assume the default revision number for each level of a version number to
be 0. For example, version number 3.4 has a revision number of 3 and 4 for its
first and second level revision number. Its third and fourth level revision
number are both 0.



Example 1:

Input: version1 = "0.1", version2 = "1.1"
Output: -1
Example 2:

Input: version1 = "1.0.1", version2 = "1"
Output: 1
Example 3:

Input: version1 = "7.5.2.4", version2 = "7.5.3"
Output: -1
Example 4:

Input: version1 = "1.01", version2 = "1.001"
Output: 0
Explanation: Ignoring leading zeroes, both “01” and “001" represent the same
number “1” Example 5:

Input: version1 = "1.0", version2 = "1.0.0"
Output: 0
Explanation: The first version number does not have a third level revision
number, which means its third level revision number is default to "0"


Note:

Version strings are composed of numeric strings separated by dots . and this
numeric strings may have leading zeroes. Version strings do not start or end
with dots, and they will not be two consecutive dots.
*/

// Simple O(N) solution
class Solution {
   public:
    int compareVersion(string version1, string version2) {
        vector<int> Q1, Q2;
        stringstream check1(version1), check2(version2);
        string curr;
        while (getline(check1, curr, '.')) Q1.push_back(stoi(curr));
        while (getline(check2, curr, '.')) Q2.push_back(stoi(curr));

        Q1.size() > Q2.size() ? Q2.resize(Q1.size()) : Q1.resize(Q2.size());

        for (int idx = 0; idx < Q1.size(); idx++) {
            if (Q1[idx] < Q2[idx])
                return -1;
            else if (Q1[idx] > Q2[idx])
                return 1;
        }

        return 0;
    }
};