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You are using wrong syntax in the first example. eqs is a vector of Num (symbolic expression). Writing eqs~[F*cos(ω*t), 0] equates the vectors so that the type would be Symbolics.Num[...] ~ Symbolics.Num[...]. However, you would to equate the indivual expressions. Broadcasting the equation symbol ~ gives Vector{Equation}, i.e., eqs .~ [F*cos(ω*t), 0] (Notice, .~ vs ~.)
For a set of equations,
gives a different result than
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