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Redundant vbCrLf #18

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GoogleCodeExporter opened this issue May 3, 2016 · 0 comments
Open

Redundant vbCrLf #18

GoogleCodeExporter opened this issue May 3, 2016 · 0 comments

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@GoogleCodeExporter
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The code lines
1) in skipchar():
While index > 0 And index <= Len(str) And InStr(vbCr & vbLf & vbTab & " ", 
Mid(str, index, 1)) 

and

2) If InStr(vbCrLf & vbCr & vbLf & vbTab & " ", char) Then

The first vbCrLf & 
is redundant as it duplicates vbCr & vbLf
AND char is only one character anyway.

(Thanks for fix to parsenumber btw)

Original issue reported on code.google.com by [email protected] on 28 Mar 2014 at 2:41

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