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The code lines
1) in skipchar():
While index > 0 And index <= Len(str) And InStr(vbCr & vbLf & vbTab & " ",
Mid(str, index, 1))
and
2) If InStr(vbCrLf & vbCr & vbLf & vbTab & " ", char) Then
The first vbCrLf &
is redundant as it duplicates vbCr & vbLf
AND char is only one character anyway.
(Thanks for fix to parsenumber btw)
Original issue reported on code.google.com by [email protected] on 28 Mar 2014 at 2:41
The text was updated successfully, but these errors were encountered:
Original issue reported on code.google.com by
[email protected]
on 28 Mar 2014 at 2:41The text was updated successfully, but these errors were encountered: