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During the execution of mipsolver.run(), if dive() is required to solve the third node poped from the nodeque, how to ensure that cuts generated from the second node is removed?
The reason for this question is: Does the situation below exist?
Cut3 is right for region 1, but wrong for region 2。
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During the execution of mipsolver.run(), if dive() is required to solve the third node poped from the nodeque, how to ensure that cuts generated from the second node is removed?
The reason for this question is: Does the situation below exist?
Cut3 is right for region 1, but wrong for region 2。
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