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DIvision par zéro dans un calcul d'HHI #2

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chgeissler opened this issue Jul 26, 2021 · 0 comments

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chgeissler commented Jul 26, 2021

L'instruction suivante provoque une erreur lorsque le vecteur w_threshold est nul.
Cela ne devrait pas arriver, mais ça arrive !

hhi = int(np.round((np.linalg.norm(w_threshold, ord=1)/np.linalg.norm(w_threshold, ord=2))**2, decimals=0))

Suggestion: ajouter un epsilon à la norme L2 au dénominateur, quand celle-ci est nulle.

chgeissler assigned paulfogel

ghost unassigned paulfogel

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