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ReferenceImplementation.qs
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ReferenceImplementation.qs
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// Copyright (c) Microsoft Corporation. All rights reserved.
// Licensed under the MIT license.
//////////////////////////////////////////////////////////////////////
// This file contains reference solutions to all tasks.
// The tasks themselves can be found in Tasks.qs file.
// We recommend that you try to solve the tasks yourself first,
// but feel free to look up the solution if you get stuck.
//////////////////////////////////////////////////////////////////////
namespace Quantum.Kata.RippleCarryAdder {
open Microsoft.Quantum.Measurement;
open Microsoft.Quantum.Arrays;
open Microsoft.Quantum.Intrinsic;
open Microsoft.Quantum.Canon;
//////////////////////////////////////////////////////////////////
// Part I. Simple adder outputting to empty Qubits
//////////////////////////////////////////////////////////////////
// Task 1.1. Summation of two bits
operation LowestBitSum_Reference (a : Qubit, b : Qubit, sum : Qubit) : Unit is Adj {
CNOT(a, sum);
CNOT(b, sum);
}
// Task 1.2. Carry of two bits
operation LowestBitCarry_Reference (a : Qubit, b : Qubit, carry : Qubit) : Unit is Adj {
CCNOT(a, b, carry);
}
// Task 1.3. One-bit adder
operation OneBitAdder_Reference (a : Qubit, b : Qubit, sum : Qubit, carry : Qubit) : Unit is Adj {
LowestBitSum_Reference(a, b, sum);
LowestBitCarry_Reference(a, b, carry);
}
// Task 1.4. Summation of 3 bits
operation HighBitSum_Reference (a : Qubit, b : Qubit, carryin : Qubit, sum : Qubit) : Unit is Adj {
CNOT(a, sum);
CNOT(b, sum);
CNOT(carryin, sum);
}
// Task 1.5. Carry of 3 bits
operation HighBitCarry_Reference (a : Qubit, b : Qubit, carryin : Qubit, carryout : Qubit) : Unit is Adj {
CCNOT(a, b, carryout);
CCNOT(a, carryin, carryout);
CCNOT(b, carryin, carryout);
}
// Task 1.6. Two-bit adder
operation TwoBitAdder_Reference (a : Qubit[], b : Qubit[], sum : Qubit[], carry : Qubit) : Unit is Adj {
use internalCarry = Qubit();
LowestBitSum_Reference(a[0], b[0], sum[0]);
LowestBitCarry_Reference(a[0], b[0], internalCarry);
HighBitSum_Reference(a[1], b[1], internalCarry, sum[1]);
HighBitCarry_Reference(a[1], b[1], internalCarry, carry);
// Clean up ancillary qubit
Adjoint LowestBitCarry_Reference(a[0], b[0], internalCarry);
}
// Task 1.7. N-bit adder
operation ArbitraryAdder_Reference (a : Qubit[], b : Qubit[], sum : Qubit[], carry : Qubit) : Unit is Adj {
let N = Length(a);
if (N == 1) {
LowestBitSum_Reference(a[0], b[0], sum[0]);
LowestBitCarry_Reference(a[0], b[0], carry);
}
else {
use internalCarries = Qubit[N-1];
LowestBitSum_Reference(a[0], b[0], sum[0]);
LowestBitCarry_Reference(a[0], b[0], internalCarries[0]);
for i in 1 .. N-2 {
HighBitSum_Reference(a[i], b[i], internalCarries[i-1], sum[i]);
HighBitCarry_Reference(a[i], b[i], internalCarries[i-1], internalCarries[i]);
}
HighBitSum_Reference(a[N-1], b[N-1], internalCarries[N-2], sum[N-1]);
HighBitCarry_Reference(a[N-1], b[N-1], internalCarries[N-2], carry);
// Clean up the ancillary qubits
for i in N-2 .. -1 .. 1 {
Adjoint HighBitCarry_Reference(a[i], b[i], internalCarries[i-1], internalCarries[i]);
}
Adjoint LowestBitCarry_Reference(a[0], b[0], internalCarries[0]);
}
}
// A slightly simpler solution - more uniform, but slightly slower, and requires one extra qubit
operation ArbitraryAdder_Simplified_Reference (a : Qubit[], b : Qubit[], sum : Qubit[], carry : Qubit) : Unit is Adj {
let N = Length(a);
use internalCarries = Qubit[N];
let carries = internalCarries + [carry];
for i in 0 .. N-1 {
HighBitSum_Reference(a[i], b[i], carries[i], sum[i]);
HighBitCarry_Reference(a[i], b[i], carries[i], carries[i+1]);
}
// Clean up the ancilla
for i in N-2 .. -1 .. 0 {
Adjoint HighBitCarry_Reference(a[i], b[i], carries[i], carries[i+1]);
}
}
// The challenge solution - the sum qubits are used to store the carry bits, and the sum is calculated as they get cleaned up
operation ArbitraryAdder_Challenge_Reference (a : Qubit[], b : Qubit[], sum : Qubit[], carry : Qubit) : Unit is Adj {
let N = Length(a);
// Calculate carry bits
LowestBitCarry_Reference(a[0], b[0], sum[0]);
for i in 1 .. N-1 {
HighBitCarry_Reference(a[i], b[i], sum[i - 1], sum[i]);
}
CNOT(sum[N-1], carry);
// Clean sum qubits and compute sum
for i in N-1 .. -1 .. 1 {
Adjoint HighBitCarry_Reference(a[i], b[i], sum[i - 1], sum[i]);
HighBitSum_Reference(a[i], b[i], sum[i - 1], sum[i]);
}
Adjoint LowestBitCarry_Reference(a[0], b[0], sum[0]);
LowestBitSum_Reference(a[0], b[0], sum[0]);
}
//////////////////////////////////////////////////////////////////
// Part II. Simple in-place adder
//////////////////////////////////////////////////////////////////
// Task 2.1. In-place summation of two bits
operation LowestBitSumInPlace_Reference (a : Qubit, b : Qubit) : Unit is Adj {
CNOT(a, b);
}
// Task 2.2. In-place one-bit adder
operation OneBitAdderInPlace_Reference (a : Qubit, b : Qubit, carry : Qubit) : Unit is Adj {
LowestBitCarry_Reference(a, b, carry);
LowestBitSumInPlace_Reference(a, b);
}
// Task 2.3. In-place summation of three bits
operation HighBitSumInPlace_Reference (a : Qubit, b : Qubit, carryin : Qubit) : Unit is Adj {
CNOT(a, b);
CNOT(carryin, b);
}
// Task 2.4. In-place two-bit adder
operation TwoBitAdderInPlace_Reference (a : Qubit[], b : Qubit[], carry : Qubit) : Unit is Adj {
use internalCarry = Qubit();
// Set up the carry bits
LowestBitCarry_Reference(a[0], b[0], internalCarry);
HighBitCarry_Reference(a[1], b[1], internalCarry, carry);
// Calculate sums and clean up the ancilla
HighBitSumInPlace_Reference(a[1], b[1], internalCarry);
Adjoint LowestBitCarry_Reference(a[0], b[0], internalCarry);
LowestBitSumInPlace_Reference(a[0], b[0]);
}
// Task 2.5. In-place N-bit adder
operation ArbitraryAdderInPlace_Reference (a : Qubit[], b : Qubit[], carry : Qubit) : Unit is Adj {
let N = Length(a);
use internalCarries = Qubit[N];
// Set up the carry bits
LowestBitCarry_Reference(a[0], b[0], internalCarries[0]);
for i in 1 .. N-1 {
HighBitCarry_Reference(a[i], b[i], internalCarries[i - 1], internalCarries[i]);
}
CNOT(internalCarries[N-1], carry);
// Clean up carry bits and compute sum
for i in N-1 .. -1 .. 1 {
Adjoint HighBitCarry_Reference(a[i], b[i], internalCarries[i - 1], internalCarries[i]);
HighBitSumInPlace_Reference(a[i], b[i], internalCarries[i - 1]);
}
Adjoint LowestBitCarry_Reference(a[0], b[0], internalCarries[0]);
LowestBitSumInPlace_Reference(a[0], b[0]);
}
//////////////////////////////////////////////////////////////////
// Part III*. Improved in-place adder
//////////////////////////////////////////////////////////////////
// Task 3.1. Majority gate
operation Majority_Reference (a : Qubit, b : Qubit, c : Qubit) : Unit is Adj {
CNOT(a, b);
CNOT(a, c);
CCNOT(b, c, a);
}
// Task 3.2. UnMajority and Add gate
operation UnMajorityAdd_Reference (a : Qubit, b : Qubit, c : Qubit) : Unit is Adj {
CCNOT(b, c, a);
CNOT(a, c);
CNOT(c, b);
}
// Task 3.3. One-bit majority-UMA adder
operation OneBitMajUmaAdder_Reference (a : Qubit, b : Qubit, carry : Qubit) : Unit is Adj {
use tempCarry = Qubit();
Majority_Reference(a, b, tempCarry);
CNOT(a, carry);
UnMajorityAdd_Reference(a, b, tempCarry);
}
// Task 3.4. Two-bit majority-UMA adder
operation TwoBitMajUmaAdder_Reference (a : Qubit[], b : Qubit[], carry : Qubit) : Unit is Adj {
use tempCarry = Qubit();
// We only need the extra qubit so we have 3 to pass to the majority gate for the lowest bits
Majority_Reference(a[0], b[0], tempCarry);
Majority_Reference(a[1], b[1], a[0]);
// Save last carry bit
CNOT(a[1], carry);
// Restore inputs/ancilla and compute sum
UnMajorityAdd_Reference(a[1], b[1], a[0]);
UnMajorityAdd_Reference(a[0], b[0], tempCarry);
}
// Task 3.5. N-bit majority-UMA adder
operation ArbitraryMajUmaAdder_Reference (a : Qubit[], b : Qubit[], carry : Qubit) : Unit is Adj {
let N = Length(a);
use tempCarry = Qubit();
let carries = [tempCarry] + a;
// Compute carry bits
for i in 0 .. N-1 {
Majority_Reference(a[i], b[i], carries[i]);
}
// Save last carry bit
CNOT(carries[N], carry);
// Restore inputs and ancilla, compute sum
for i in N-1 .. -1 .. 0 {
UnMajorityAdd_Reference(a[i], b[i], carries[i]);
}
}
//////////////////////////////////////////////////////////////////
// Part IV*. In-place subtractor
//////////////////////////////////////////////////////////////////
// Task 4.1. N-bit subtractor
operation Subtractor_Reference (a : Qubit[], b : Qubit[], borrowBit : Qubit) : Unit is Adj {
// transform b into 2ᴺ - 1 - b
ApplyToEachA(X, b);
// compute (2ᴺ - 1 - b) + a = 2ᴺ - 1 - (b - a) using existing adder
// if this produced a carry, then (2ᴺ - 1 - (b - a)) > 2ᴺ - 1, so (b - a) < 0, and we need a borrow
// this means we can use the carry qubit from the addition as the borrow qubit
ArbitraryMajUmaAdder_Reference(a, b, borrowBit);
// transform 2ᴺ - 1 - (b - a) into b - a
ApplyToEachA(X, b);
}
//////////////////////////////////////////////////////////////////
// Part V. Addition and subtraction modulo 2ᴺ
//////////////////////////////////////////////////////////////////
// Task 5.1. Adder Modulo 2ᴺ
operation AdderModuloN_Reference (a : Qubit[], b : Qubit[], sum : Qubit[]) : Unit is Adj {
// Modification of challenge solution of task 1.7 (last carry bit isn't calculated).
// Sum qubits are used to store the carry bits, and the sum is calculated as they get cleaned up.
// (It's also possible to use a similar modification of regular solution of task 1.7.)
let N = Length(a);
// Calculate carry bits and Store them in Sum
LowestBitCarry_Reference(a[0], b[0], sum[0]);
for i in 1 .. N-1 {
HighBitCarry_Reference(a[i], b[i], sum[i - 1], sum[i]);
}
// No need to calculated last (N+1)th carry bit, as addition is modulo 2ᴺ.
// Clean sum qubits (uncompute carries after they aren't needed) and compute sum
for i in N-1 .. -1 .. 1 {
Adjoint HighBitCarry_Reference(a[i], b[i], sum[i - 1], sum[i]); // Restore sum[i] to state 0
HighBitSum_Reference(a[i], b[i], sum[i - 1], sum[i]); // Compute sum[i]
}
Adjoint LowestBitCarry_Reference(a[0], b[0], sum[0]); // Restore sum[0] to state 0
LowestBitSum_Reference(a[0], b[0], sum[0]); // Compute sum[i]
}
// Task 5.2. Two's Complement
operation TwosComplement_Reference (a : Qubit[]) : Unit is Adj {
// Transform a into 2ᴺ - 1 - a ("one's complement")
ApplyToEachA(X, a);
// Increment mod 2ᴺ.
// Since we are incrementing by 1, we flip the next most significant bit only if all previous bits are 0.
for prefix in Prefixes(a) {
(ControlledOnInt(0, X))(Most(prefix), Tail(prefix));
}
}
// Task 5.3. Subtractor Modulo 2ᴺ
operation SubtractorModuloN_Reference (a : Qubit[], b : Qubit[], diff : Qubit[]) : Unit is Adj {
within {
// Transform a into its Two's Complement 2ᴺ - a
TwosComplement_Reference(a);
} apply {
// Add 2ᴺ - a and b to get (2ᴺ + b - a) mod 2ᴺ = (b-a) mod 2ᴺ
AdderModuloN_Reference(a, b, diff);
}
}
// Task 5.4. In-place adder modulo 2ᴺ
operation InPlaceAdderModuloN_Reference (a : Qubit[], b : Qubit[]) : Unit is Adj {
// Modification of task 3.5 solution (last carry bit isn't calculated)
use tempCarry = Qubit();
let carries = [tempCarry] + a;
// Compute carry bits
ApplyToEachA(Majority_Reference, Zipped3(a, b, carries));
// No need to save last (N+1)th carry bit
// Restore inputs and ancilla, compute sum
ApplyToEachA(UnMajorityAdd_Reference, Reversed(Zipped3(a, b, carries)));
}
// Task 5.5. In-place subtractor modulo 2ᴺ
operation InPlaceSubtractorModuloN_Reference (a : Qubit[], b : Qubit[]) : Unit is Adj {
// Notice that Task 5.4 is actually the Adjoint of Task 5.3.
// Task 5.3 maps (a,b) -> (a,(a+b)mod2ᴺ). Let c = (a+b)mod2ᴺ
// Task 5.4 maps (a,b) -> (a,(b-a)mod2ᴺ). So Task 5.4 will maps (a,c) -> (a,(c-a)mod2ᴺ) = (a,((a+b)mod2ᴺ-a)mod2ᴺ) = (a,b).
Adjoint InPlaceAdderModuloN_Reference(a, b);
}
}